2. Induction
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2.1 Data Types as Inductively Defined Mathematical Collections
All the notions which were studied until now pertain to traditional mathematical logic. Specifications of objects were abstract properties used in reasoning more or less constructively; we are now entering the realm of inductive types, which specify the existence of concrete mathematical constructions.
2.1.1 Booleans
Let us start with the collection of booleans, as they are specified
in the Coq’s Prelude
module:
bool is defined
bool_rect is defined
bool_ind is defined
bool_rec is defined
Such a declaration defines several objects at once. First, a new
Set
is declared, with name bool
. Then the constructors
of this Set
are declared, called true
and false
.
Those are analogous to introduction rules of the new Set bool
.
Finally, a specific elimination rule for bool
is now available, which
permits to reason by cases on bool
values. Three instances are
indeed defined as new combinators in the global context: bool_ind
,
a proof combinator corresponding to reasoning by cases,
bool_rec
, an if-then-else programming construct,
and bool_rect
, a similar combinator at the level of types.
Indeed:
bool_ind
: forall P : bool -> Prop,
P true -> P false -> forall b : bool, P b
Coq < Check bool_rec.
bool_rec
: forall P : bool -> Set,
P true -> P false -> forall b : bool, P b
Coq < Check bool_rect.
bool_rect
: forall P : bool -> Type,
P true -> P false -> forall b : bool, P b
Let us for instance prove that every Boolean is true or false.
1 subgoal
============================
forall b : bool, b = true \/ b = false
Coq < intro b.
1 subgoal
b : bool
============================
b = true \/ b = false
We use the knowledge that b
is a bool
by calling tactic
elim
, which is this case will appeal to combinator bool_ind
in order to split the proof according to the two cases:
2 subgoals
b : bool
============================
true = true \/ true = false
subgoal 2 is:
false = true \/ false = false
It is easy to conclude in each case:
1 subgoal
b : bool
============================
false = true \/ false = false
Coq < right; trivial.
No more subgoals.
Indeed, the whole proof can be done with the combination of the
destruct
, which combines intro
and elim
,
with good old auto
:
1 subgoal
============================
forall b : bool, b = true \/ b = false
Coq < destruct b; auto.
No more subgoals.
Coq < Qed.
duality is defined
2.1.2 Natural numbers
Similarly to Booleans, natural numbers are defined in the Prelude
module with constructors S
and O
:
| O : nat
| S : nat -> nat.
nat is defined
nat_rect is defined
nat_ind is defined
nat_rec is defined
The elimination principles which are automatically generated are Peano’s induction principle, and a recursion operator:
nat_ind
: forall P : nat -> Prop,
P O ->
(forall n : nat, P n -> P (S n)) ->
forall n : nat, P n
Coq < Check nat_rec.
nat_rec
: forall P : nat -> Set,
P O ->
(forall n : nat, P n -> P (S n)) ->
forall n : nat, P n
Let us start by showing how to program the standard primitive recursion
operator prim_rec
from the more general nat_rec
:
prim_rec is defined
That is, instead of computing for natural i
an element of the indexed
Set
(P i)
, prim_rec
computes uniformly an element of
nat
. Let us check the type of prim_rec
:
prim_rec :
(fun _ : nat => nat) O ->
(forall n : nat,
(fun _ : nat => nat) n -> (fun _ : nat => nat) (S n)) ->
forall n : nat, (fun _ : nat => nat) n
Argument scopes are [_ function_scope _]
prim_rec is transparent
Expands to: Constant Top.prim_rec
Oops! Instead of the expected type nat->(nat->nat->nat)->nat->nat
we
get an apparently more complicated expression.
In fact, the two types are convertible and one way of having the proper
type would be to do some computation before actually defining prim_rec
as such:
Eval compute in nat_rec (fun i : nat => nat).
prim_rec is defined
Coq < About prim_rec.
prim_rec : nat -> (nat -> nat -> nat) -> nat -> nat
Argument scopes are [nat_scope function_scope nat_scope]
prim_rec is transparent
Expands to: Constant Top.prim_rec
Let us now show how to program addition with primitive recursion:
prim_rec m (fun p rec : nat => S rec) n.
addition is defined
That is, we specify that (addition n m)
computes by cases on n
according to its main constructor; when n = O
, we get m
;
when n = S p
, we get (S rec)
, where rec
is the result
of the recursive computation (addition p m)
. Let us verify it by
asking Coq to compute for us say 2+3:
= 5
: nat
Actually, we do not have to do all explicitly. Coq provides a special syntax Fixpoint/match for generic primitive recursion, and we could thus have defined directly addition as:
match n with
| O => m
| S p => S (plus p m)
end.
plus is defined
plus is recursively defined (decreasing on 1st argument)
2.1.3 Simple proofs by induction
Let us now show how to do proofs by structural induction. We start with easy
properties of the plus
function we just defined. Let us first
show that n=n+0.
1 subgoal
============================
forall n : nat, n = n + 0
Coq < intro n; elim n.
2 subgoals
n : nat
============================
0 = 0 + 0
subgoal 2 is:
forall n0 : nat, n0 = n0 + 0 -> S n0 = S n0 + 0
What happened was that elim n, in order to construct a Prop (the initial goal) from a nat (i.e. n), appealed to the corresponding induction principle nat_ind which we saw was indeed exactly Peano’s induction scheme. Pattern-matching instantiated the corresponding predicate P to fun n : nat => n = n + 0, and we get as subgoals the corresponding instantiations of the base case (P O), and of the inductive step forall y : nat, P y -> P (S y). In each case we get an instance of function plus in which its second argument starts with a constructor, and is thus amenable to simplification by primitive recursion. The Coq tactic simpl can be used for this purpose:
2 subgoals
n : nat
============================
0 = 0
subgoal 2 is:
forall n0 : nat, n0 = n0 + 0 -> S n0 = S n0 + 0
Coq < auto.
1 subgoal
n : nat
============================
forall n0 : nat, n0 = n0 + 0 -> S n0 = S n0 + 0
We proceed in the same way for the base step:
No more subgoals.
Coq < Qed.
plus_n_O is defined
Here auto
succeeded, because it used as a hint lemma eq_S
,
which say that successor preserves equality:
eq_S
: forall x y : nat, x = y -> S x = S y
Actually, let us see how to declare our lemma plus_n_O
as a hint
to be used by auto
:
We now proceed to the similar property concerning the other constructor
S
:
1 subgoal
============================
forall n m : nat, S (n + m) = n + S m
We now go faster, using the tactic induction
, which does the
necessary intros
before applying elim
. Factoring simplification
and automation in both cases thanks to tactic composition, we prove this
lemma in one line:
No more subgoals.
Coq < Qed.
plus_n_S is defined
Coq < Hint Resolve plus_n_S .
Let us end this exercise with the commutativity of plus
:
1 subgoal
============================
forall n m : nat, n + m = m + n
Here we have a choice on doing an induction on n
or on m
, the
situation being symmetric. For instance:
1 subgoal
n, m : nat
IHm : n + m = m + n
============================
n + S m = S (m + n)
Here auto
succeeded on the base case, thanks to our hint
plus_n_O
, but the induction step requires rewriting, which
auto
does not handle:
No more subgoals.
Coq < Qed.
plus_com is defined
2.1.4 Discriminate
It is also possible to define new propositions by primitive recursion.
Let us for instance define the predicate which discriminates between
the constructors O
and S
: it computes to False
when its argument is O
, and to True
when its argument is
of the form (S n)
:
| O => False
| S p => True
end.
Is_S is defined
Now we may use the computational power of Is_S
to prove
trivially that (Is_S (S n))
:
1 subgoal
============================
forall n : nat, Is_S (S n)
Coq < simpl; trivial.
No more subgoals.
Coq < Qed.
S_Is_S is defined
But we may also use it to transform a False
goal into
(Is_S O)
. Let us show a particularly important use of this feature;
we want to prove that O
and S
construct different values, one
of Peano’s axioms:
1 subgoal
============================
forall n : nat, 0 <> S n
First of all, we replace negation by its definition, by reducing the
goal with tactic red
; then we get contradiction by successive
intros
:
1 subgoal
n : nat
H : 0 = S n
============================
False
Now we use our trick:
1 subgoal
n : nat
H : 0 = S n
============================
Is_S 0
Now we use equality in order to get a subgoal which computes out to
True
, which finishes the proof:
1 subgoal
n : nat
H : 0 = S n
============================
Is_S (S n)
Coq < simpl; trivial.
No more subgoals.
Actually, a specific tactic discriminate
is provided
to produce mechanically such proofs, without the need for the user to define
explicitly the relevant discrimination predicates:
1 subgoal
============================
forall n : nat, 0 <> S n
Coq < intro n; discriminate.
No more subgoals.
Coq < Qed.
no_confusion is defined
2.2 Logic programming
In the same way as we defined standard data-types above, we
may define inductive families, and for instance inductive predicates.
Here is the definition of predicate ≤ over type nat
, as
given in Coq’s Prelude
module:
| le_n : le n n
| le_S : forall m : nat, le n m -> le n (S m).
This definition introduces a new predicate
le : nat -> nat -> Prop
,
and the two constructors le_n
and le_S
, which are the
defining clauses of le
. That is, we get not only the “axioms”
le_n
and le_S
, but also the converse property, that
(le n m)
if and only if this statement can be obtained as a
consequence of these defining clauses; that is, le
is the
minimal predicate verifying clauses le_n
and le_S
. This is
insured, as in the case of inductive data types, by an elimination principle,
which here amounts to an induction principle le_ind
, stating this
minimality property:
le
: nat -> nat -> Prop
Coq < Check le_ind.
le_ind
: forall (n : nat) (P : nat -> Prop),
P n ->
(forall m : nat, le n m -> P m -> P (S m)) ->
forall n0 : nat, le n n0 -> P n0
Let us show how proofs may be conducted with this principle. First we show that n≤ m ⇒ n+1≤ m+1:
1 subgoal
============================
forall n m : nat, le n m -> le (S n) (S m)
Coq < intros n m n_le_m.
1 subgoal
n, m : nat
n_le_m : le n m
============================
le (S n) (S m)
Coq < elim n_le_m.
2 subgoals
n, m : nat
n_le_m : le n m
============================
le (S n) (S n)
subgoal 2 is:
forall m0 : nat,
le n m0 -> le (S n) (S m0) -> le (S n) (S (S m0))
What happens here is similar to the behaviour of elim
on natural
numbers: it appeals to the relevant induction principle, here le_ind
,
which generates the two subgoals, which may then be solved easily
with the help of the defining clauses of le
.
1 subgoal
n, m : nat
n_le_m : le n m
============================
forall m0 : nat,
le n m0 -> le (S n) (S m0) -> le (S n) (S (S m0))
Coq < intros; apply le_S; trivial.
No more subgoals.
Now we know that it is a good idea to give the defining clauses as hints,
so that the proof may proceed with a simple combination of
induction
and auto
. Hint Constructors le
is just an abbreviation for Hint Resolve le_n le_S
.
Coq < Lemma le_n_S : forall n m : nat, le n m -> le (S n) (S m).
1 subgoal
============================
forall n m : nat, le n m -> le (S n) (S m)
We have a slight problem however. We want to say “Do an induction on
hypothesis (le n m)
”, but we have no explicit name for it. What we
do in this case is to say “Do an induction on the first unnamed hypothesis”,
as follows.
No more subgoals.
Coq < Qed.
le_n_S is defined
Here is a more tricky problem. Assume we want to show that
n≤ 0 ⇒ n=0. This reasoning ought to follow simply from the
fact that only the first defining clause of le
applies.
1 subgoal
============================
forall n : nat, le n 0 -> n = 0
However, here trying something like induction 1
would lead
nowhere (try it and see what happens).
An induction on n
would not be convenient either.
What we must do here is analyse the definition of le
in order
to match hypothesis (le n O)
with the defining clauses, to find
that only le_n
applies, whence the result.
This analysis may be performed by the “inversion” tactic
inversion_clear
as follows:
1 subgoal
n : nat
============================
0 = 0
Coq < trivial.
No more subgoals.
Coq < Qed.
tricky is defined